Hi, in typescript, how can I handle sql errors so I can return the correct message to the client ` const body = await request.json(); context.extraOutputs.set(sqlOutput, body); return { status: 201 };`
Hi, in typescript, how can I handle sql errors so I can return the correct message to the client
const body = await request.json(); context.extraOutputs.set(sqlOutput, body); return { status: 201 };