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"""
Given the root of a binary tree, invert the tree, and return its root.
Example 1:
Input: root = [4,2,7,1,3,6,9]
Output: [4,7,2,9,6,3,1]
Example 2:
Input: root = [2,1,3]
Output: [2,3,1]
Example 3:
Input: root = []
Output: []
Constraints:
The number of nodes in the tree is in the range [0, 100].
-100 <= Node.val <= 100
"""
# Definition for a binary tree node.
class TreeNode:
def __init__(self, val=0, left=None, right=None):
self.val = val
self.left = left
self.right = right
class Solution:
def invertTree(self, root: Optional[TreeNode]) -> Optional[TreeNode]:
# Base case: if the tree is empty, return None
if not root:
return None
# Invert the left and right subtrees
root.left, root.right = self.invertTree(root.right), self.invertTree(root.left)
return root
# Example usage:
# Create a binary tree
tree = TreeNode(4)
tree.left = TreeNode(2)
tree.right = TreeNode(7)
tree.left.left = TreeNode(1)
tree.left.right = TreeNode(3)
tree.right.left = TreeNode(6)
tree.right.right = TreeNode(9)
solution = Solution()
inverted_tree = solution.invertTree(tree)
# You can now traverse and print the inverted tree to see the result.