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Submitting Q1 - #463

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akshay4121 wants to merge 1 commit into
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Open

Submitting Q1#463
akshay4121 wants to merge 1 commit into
super30admin:masterfrom
akshay4121:master

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@akshay4121

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@super30admin

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Your solution is correct and efficient, running in O(n) time and using O(1) space. However, there are a few points to improve:

  1. Variable Naming: The variable names minL and maxL are not very descriptive. Consider using minPrice and maxPrice or currentMin and currentMax to make the code more readable.

  2. Simplicity: There is a simpler approach to this problem: you can simply iterate through the array and add every positive difference between consecutive days. This would make the code shorter and easier to understand. For example:
    int profit = 0;
    for (int i = 1; i < prices.length; i++) {
    if (prices[i] > prices[i-1]) {
    profit += prices[i] - prices[i-1];
    }
    }
    return profit;

  3. Edge Cases: Your code handles edge cases correctly, but the simpler method would be even more straightforward.

  4. Comments

@super30admin

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Your solution is correct and efficient, with O(n) time and O(1) space complexity. This is a good approach, but it is more complex than necessary. The standard solution for this problem is to simply add the difference whenever the current price is higher than the previous day's price. For example:

int profit = 0;
for (int i = 1; i < prices.length; i++) {
    if (prices[i] > prices[i-1]) {
        profit += prices[i] - prices[i-1];
    }
}
return profit;

This approach is simpler and achieves the same result. Your method of tracking local minima and maxima is valid, but it requires more code and has edge cases to handle (like the final segment). The standard solution is more straightforward.

Strengths:

  • You identified a greedy approach that works.
  • The code is efficient and uses constant space.

Areas for improvement:

  • Variable names could be more descriptive (e.g., minPrice and maxPrice instead of minL and maxL).
  • The logic can be simplified to the standard solution, which is easier to understand and maintain.
  • Consider adding comments to explain the approach.

Overall, your solution is correct, but I recommend adopting the simpler standard solution for clarity.

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